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Chapter 2: Analyzing Games: From Optimality to Equilibrium 

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 Page number:12
 Section number:2.3
 Date:3/13/12
 Name:Julian Fogel
 Email:filos2@yahoo.com
 Content:The expression $U_{wife}(LW)$ is not precisely defined. The reader is left to guess what it refers to exactly. My guess is that we could define $u_{(i,j)}$ in a similar fashion as $s_{j}$, and that $U_{wife}(LW)$ is $u_{(1,2)}(LW)$.


 Page number:10
 Section number:2.2
 Date:3/13/12
 Name:Julian Fogel
 Email:filos2@yahoo.com


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 Content:writing $s=(s_i,s_{i}) contradicts the definition that $s$ is a member of the Cartesian product $S_1X...XS_n$. The order in a Cartesian product matters, as does nesting. $(s_i,s_{1})$ is a member of S_iX(S_1X...S_{i1}XS_{i+1}X...XS_n which is not the same as S_1X...XS_n).This may especially lead to confusion in the case of 2player games, when $i=2$ and the order of the first and second player gets swapped: $s = (s_2,s_1)$.

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 Content:Writing $s=(s_i,s_{i})$ contradicts the definition that $s$ is a member of the Cartesian product $S_1X...XS_n$. The order in a Cartesian product matters, as does nesting. $(s_i,s_{i})$ is a member of $S_iX(S_1X...S_{i1}XS_{i+1}X...XS_n)$ which is not the same as $S_1X...XS_n$.This may especially lead to confusion in the case of 2player games, when $i=2$ since the order of the first and second player gets swapped: $s = (s_i,s_{i}) = (s_2,s_1)$. But we also have by definition that $s = (s_1,s_2)$.


